Optimal. Leaf size=75 \[ \frac {d (c d-b e) (d+e x)^{1+m}}{e^3 (1+m)}-\frac {(2 c d-b e) (d+e x)^{2+m}}{e^3 (2+m)}+\frac {c (d+e x)^{3+m}}{e^3 (3+m)} \]
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Rubi [A]
time = 0.03, antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 1, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {712}
\begin {gather*} \frac {d (c d-b e) (d+e x)^{m+1}}{e^3 (m+1)}-\frac {(2 c d-b e) (d+e x)^{m+2}}{e^3 (m+2)}+\frac {c (d+e x)^{m+3}}{e^3 (m+3)} \end {gather*}
Antiderivative was successfully verified.
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Rule 712
Rubi steps
\begin {align*} \int (d+e x)^m \left (b x+c x^2\right ) \, dx &=\int \left (\frac {d (c d-b e) (d+e x)^m}{e^2}+\frac {(-2 c d+b e) (d+e x)^{1+m}}{e^2}+\frac {c (d+e x)^{2+m}}{e^2}\right ) \, dx\\ &=\frac {d (c d-b e) (d+e x)^{1+m}}{e^3 (1+m)}-\frac {(2 c d-b e) (d+e x)^{2+m}}{e^3 (2+m)}+\frac {c (d+e x)^{3+m}}{e^3 (3+m)}\\ \end {align*}
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Mathematica [A]
time = 0.06, size = 75, normalized size = 1.00 \begin {gather*} \frac {d (c d-b e) (d+e x)^{1+m}}{e^3 (1+m)}-\frac {(2 c d-b e) (d+e x)^{2+m}}{e^3 (2+m)}+\frac {c (d+e x)^{3+m}}{e^3 (3+m)} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.43, size = 116, normalized size = 1.55
method | result | size |
gosper | \(-\frac {\left (e x +d \right )^{1+m} \left (-c \,e^{2} m^{2} x^{2}-b \,e^{2} m^{2} x -3 c \,e^{2} m \,x^{2}-4 b \,e^{2} m x +2 c d e m x -2 c \,x^{2} e^{2}+b d e m -3 b \,e^{2} x +2 c d e x +3 b d e -2 c \,d^{2}\right )}{e^{3} \left (m^{3}+6 m^{2}+11 m +6\right )}\) | \(116\) |
norman | \(\frac {c \,x^{3} {\mathrm e}^{m \ln \left (e x +d \right )}}{3+m}+\frac {\left (b e m +c d m +3 b e \right ) x^{2} {\mathrm e}^{m \ln \left (e x +d \right )}}{e \left (m^{2}+5 m +6\right )}+\frac {m d \left (b e m +3 b e -2 c d \right ) x \,{\mathrm e}^{m \ln \left (e x +d \right )}}{e^{2} \left (m^{3}+6 m^{2}+11 m +6\right )}-\frac {d^{2} \left (b e m +3 b e -2 c d \right ) {\mathrm e}^{m \ln \left (e x +d \right )}}{e^{3} \left (m^{3}+6 m^{2}+11 m +6\right )}\) | \(149\) |
risch | \(-\frac {\left (-c \,e^{3} m^{2} x^{3}-b \,e^{3} m^{2} x^{2}-c d \,e^{2} m^{2} x^{2}-3 c \,e^{3} m \,x^{3}-b d \,e^{2} m^{2} x -4 b \,e^{3} m \,x^{2}-c d \,e^{2} m \,x^{2}-2 c \,x^{3} e^{3}-3 b d \,e^{2} m x -3 b \,e^{3} x^{2}+2 c \,d^{2} e m x +b \,d^{2} e m +3 b \,d^{2} e -2 c \,d^{3}\right ) \left (e x +d \right )^{m}}{\left (2+m \right ) \left (3+m \right ) \left (1+m \right ) e^{3}}\) | \(164\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 116, normalized size = 1.55 \begin {gather*} \frac {{\left ({\left (m + 1\right )} x^{2} e^{2} + d m x e - d^{2}\right )} b e^{\left (m \log \left (x e + d\right ) - 2\right )}}{m^{2} + 3 \, m + 2} + \frac {{\left ({\left (m^{2} + 3 \, m + 2\right )} x^{3} e^{3} + {\left (m^{2} + m\right )} d x^{2} e^{2} - 2 \, d^{2} m x e + 2 \, d^{3}\right )} c e^{\left (m \log \left (x e + d\right ) - 3\right )}}{m^{3} + 6 \, m^{2} + 11 \, m + 6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.02, size = 129, normalized size = 1.72 \begin {gather*} \frac {{\left (2 \, c d^{3} + {\left ({\left (c m^{2} + 3 \, c m + 2 \, c\right )} x^{3} + {\left (b m^{2} + 4 \, b m + 3 \, b\right )} x^{2}\right )} e^{3} + {\left ({\left (c d m^{2} + c d m\right )} x^{2} + {\left (b d m^{2} + 3 \, b d m\right )} x\right )} e^{2} - {\left (2 \, c d^{2} m x + b d^{2} m + 3 \, b d^{2}\right )} e\right )} {\left (x e + d\right )}^{m} e^{\left (-3\right )}}{m^{3} + 6 \, m^{2} + 11 \, m + 6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 1095 vs.
\(2 (63) = 126\).
time = 0.49, size = 1095, normalized size = 14.60 \begin {gather*} \begin {cases} d^{m} \left (\frac {b x^{2}}{2} + \frac {c x^{3}}{3}\right ) & \text {for}\: e = 0 \\- \frac {b d e}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} - \frac {2 b e^{2} x}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} + \frac {2 c d^{2} \log {\left (\frac {d}{e} + x \right )}}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} + \frac {3 c d^{2}}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} + \frac {4 c d e x \log {\left (\frac {d}{e} + x \right )}}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} + \frac {4 c d e x}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} + \frac {2 c e^{2} x^{2} \log {\left (\frac {d}{e} + x \right )}}{2 d^{2} e^{3} + 4 d e^{4} x + 2 e^{5} x^{2}} & \text {for}\: m = -3 \\\frac {b d e \log {\left (\frac {d}{e} + x \right )}}{d e^{3} + e^{4} x} + \frac {b d e}{d e^{3} + e^{4} x} + \frac {b e^{2} x \log {\left (\frac {d}{e} + x \right )}}{d e^{3} + e^{4} x} - \frac {2 c d^{2} \log {\left (\frac {d}{e} + x \right )}}{d e^{3} + e^{4} x} - \frac {2 c d^{2}}{d e^{3} + e^{4} x} - \frac {2 c d e x \log {\left (\frac {d}{e} + x \right )}}{d e^{3} + e^{4} x} + \frac {c e^{2} x^{2}}{d e^{3} + e^{4} x} & \text {for}\: m = -2 \\- \frac {b d \log {\left (\frac {d}{e} + x \right )}}{e^{2}} + \frac {b x}{e} + \frac {c d^{2} \log {\left (\frac {d}{e} + x \right )}}{e^{3}} - \frac {c d x}{e^{2}} + \frac {c x^{2}}{2 e} & \text {for}\: m = -1 \\- \frac {b d^{2} e m \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} - \frac {3 b d^{2} e \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {b d e^{2} m^{2} x \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {3 b d e^{2} m x \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {b e^{3} m^{2} x^{2} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {4 b e^{3} m x^{2} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {3 b e^{3} x^{2} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {2 c d^{3} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} - \frac {2 c d^{2} e m x \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {c d e^{2} m^{2} x^{2} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {c d e^{2} m x^{2} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {c e^{3} m^{2} x^{3} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {3 c e^{3} m x^{3} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} + \frac {2 c e^{3} x^{3} \left (d + e x\right )^{m}}{e^{3} m^{3} + 6 e^{3} m^{2} + 11 e^{3} m + 6 e^{3}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 263 vs.
\(2 (77) = 154\).
time = 1.59, size = 263, normalized size = 3.51 \begin {gather*} \frac {{\left (x e + d\right )}^{m} c m^{2} x^{3} e^{3} + {\left (x e + d\right )}^{m} c d m^{2} x^{2} e^{2} + {\left (x e + d\right )}^{m} b m^{2} x^{2} e^{3} + 3 \, {\left (x e + d\right )}^{m} c m x^{3} e^{3} + {\left (x e + d\right )}^{m} b d m^{2} x e^{2} + {\left (x e + d\right )}^{m} c d m x^{2} e^{2} - 2 \, {\left (x e + d\right )}^{m} c d^{2} m x e + 4 \, {\left (x e + d\right )}^{m} b m x^{2} e^{3} + 2 \, {\left (x e + d\right )}^{m} c x^{3} e^{3} + 3 \, {\left (x e + d\right )}^{m} b d m x e^{2} - {\left (x e + d\right )}^{m} b d^{2} m e + 2 \, {\left (x e + d\right )}^{m} c d^{3} + 3 \, {\left (x e + d\right )}^{m} b x^{2} e^{3} - 3 \, {\left (x e + d\right )}^{m} b d^{2} e}{m^{3} e^{3} + 6 \, m^{2} e^{3} + 11 \, m e^{3} + 6 \, e^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.37, size = 146, normalized size = 1.95 \begin {gather*} {\left (d+e\,x\right )}^m\,\left (\frac {c\,x^3\,\left (m^2+3\,m+2\right )}{m^3+6\,m^2+11\,m+6}-\frac {d^2\,\left (3\,b\,e-2\,c\,d+b\,e\,m\right )}{e^3\,\left (m^3+6\,m^2+11\,m+6\right )}+\frac {x^2\,\left (m+1\right )\,\left (3\,b\,e+b\,e\,m+c\,d\,m\right )}{e\,\left (m^3+6\,m^2+11\,m+6\right )}+\frac {d\,m\,x\,\left (3\,b\,e-2\,c\,d+b\,e\,m\right )}{e^2\,\left (m^3+6\,m^2+11\,m+6\right )}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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